17th Oct Electrochemistry Quiz 7 – Punjab Meritorious School Preparation Portal

Welcome to your 17th Oct Electrochemistry Quiz 7 CBT TEST

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If 0.5-amp current is passed through acidified silver nitrate solution for 100 minutes. The mass of silver deposited on cathode, is (eq.wt. of silver nitrate=108)

2.3523 g

3.3575 g

5.3578 g

6.3575 g

The amount of chlorine evolved by passing 2A of current in aq. solution of NaCl for 30 minutes is:

0.84 gm

1.32 gm

3.34 gm

5.47 gm

Find the charge in coulombs required to convert 0.2 mole VO₃^-2 into VO₄^-3 -

1.93 x 104

9.65 x 104

1.93 x 105

9.65 x 105

An electrolytic cell contains a solution of Ag2SO4 and has platinum electrodes. A current is passed until 1.6 gm O2 has been liberated at anode. The amount of silver deposited at cathode would be

107.88 gm

1.6 gm

0.8 gm

21.60 gm

How much chlorine will be liberated on passing one ampere current for 30 min. through NaCl solution?

0.66 mole

0.33 mole

0.66 g

0.33 g

Using same quantity of current, which among Na, Mg, and Al is deposited to the highest extent during electrolysis.

All in same amount

When an electric current of 0.5 ampere is passed through acidulated water for two hours, then volume of hydrogen (H2) at NTP produced will be (1 Coulomb of electricity deposits 0.00001 gm of hydrogen)

0.1 litre

0.6 litre

0.4 litre

0.8 litre

When electric current is passed through acidified water, 112 ml of hydrogen gas at STP collected at the cathode in 965 seconds. The current passed in amperes is

1.0

0.5

0.1

2.0

When 9650 coulombs of electricity is passed through a solution of copper sulphate, the amount of copper deposited is (given at. wt. of Cu = 63.6)

0318g

3.18 g

31.8g

63.6 g

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