27th Dec Atomic Structure Quiz 2 – Punjab Meritorious School Preparation Portal

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What is the maximum number of orbitals that can be identified with the following quantum numbers? (n=3, I=1, m₁ = 0)

Be²⁺ is isoelectronic with which of the following ions?

If n=6, the correct sequence for filling of electrons will be:

ns→ (n-2)f→ (n - 1)d → np

ns→ (n-1)d→ (n - 2)f→ np

ns→ (n - 2)f→np→ (n - 1)d

ns→np→ (n - 1)d→ (n - 2)f

Calculate the energy in joule corresponding to light of wavelength (Planck's constant h=6.63 x 10^-34 Js; speed of light c = 3 x 10⁸ ms^-¹)

Maximum number of electrons in a subshell of an atom is determined by the following:

The orbital angular momentum of a p-electron is given as:

The value of Planck's constant is 6.63 x 10^-34 Js. The speed of light is 3 x 10¹⁷ nm s¹. Which value is closest to the wavelength in nanometer of a quantum of light with frequency of 6 x 10¹⁵ s¹?

The energies E1 and E2 of two radiations are 25 eV and 50 eV, respectively. The relation between their wavelengths i.e., 2, and 22 will be:

The total number of atomic orbitals in fourth energy level of an atom is:

Larger the value of n, the larger is the orbit radius.

Equation can be used to calculate the change in energy when the electron changes orbit.

For n = 1, the electron has a more negative energy than it does for n = 6 which mean that the electron is more loosely bound in the smallest allowed orbit.

The negative sign in equation simply means that the energy or electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus.

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